One golden relation governs cars, trains, boats, runners, and escalators: Distance = Speed × Time. Everything else is unit conversion, averaging correctly, or adding/subtracting speeds when two things move.
Distance = Speed × Time
Derivatives (rearranged, same relation):
Speed = Distance / TimeTime = Distance / SpeedIntuition: Speed is distance per unit time. If you go 60 km in 2 h, speed = 30 km/h. Think "for 1 hour, how far?" → divide distance by time.
| Conversion | Multiply by | Remember |
|---|---|---|
km/h → m/s |
5/18 (÷3.6) |
90 km/h = 25 m/s, 36→10, 72→20 |
m/s → km/h |
18/5 (×3.6) |
20 m/s = 72 km/h |
Warning: average speed is NOT (S₁+S₂)/2 — that arithmetic mean
ignores time weighting.
Average Speed = Total Distance / Total Time
Go A→B at speed x, return B→A at y (equal distances):
Average Speed = (2 × x × y) / (x + y) — harmonic mean of x, y.
2×40×60/100=48. Derivation: total 2d, time = d/x + d/y → avg = 2/(1/x+1/y).| Situation | Formula | Use |
|---|---|---|
| Same direction | Srel = Sfast − Sslow |
Overtaking — faster must close the gap |
| Opposite direction | Srel = S₁ + S₂ |
Meeting / collision — they rush toward each other |
Meeting time:
Time to meet = Initial Separation / Relative Speed
LT (train length)
LT + LP
LT₁ + LT₂, speed =
Srel (add if opposite, subtract if same)
Full SVGs and worked times are in Module 06 — the principle here is tail must clear.
B: boat in still waterC: current speedD = B + CU = B − CB = (D+U)/2, C = (D−U)/2 — average and
half-difference.
Same as Module 06 — here just the definitions for speed problems.
D/(D−x).
Time = Circumference / Srel. Same direction: Srel = S₁−S₂ (faster
gains one lap); opposite: S₁+S₂. (Full details in Module 24.)
If increasing speed by Δ saves T minutes over the same distance D:
(D / Old_Speed) − (D / New_Speed) = Time_Difference
D/40 − D/60 =0.5 → D(1/40−1/60)=0.5 → D×(1/120)=0.5 →
D=60 km.
Speed = Man + Escalator
Speed = Man − Escalator
Formally identical to downstream/upstream — the medium moves.
| Symbol | Meaning |
|---|---|
D |
Distance (m, km) |
S, v |
Speed (m/s, km/h) |
t |
Time (s, h) |
u |
Initial velocity (acceleration problems) |
a |
Acceleration (m/s²) |
L |
Length (train, tunnel) |
Golden formula?
90 km/h in m/s?
Equal distances at x and y → avg speed?
Same direction, Srel=?
Train crossing platform → distance?
Boats: Downstream D and Upstream U → B=?
Saving time: increasing speed saves T. Equation?
Walking with escalator → speed?
D ⇒ S×T ; S ⇒ D/T ; T ⇒ D/S
Units ⇒ km/h→m/s ×5/18 ; m/s→km/h ×18/5
Avg ⇒ total D / total T ; equal D ⇒ 2xy/(x+y) (harmonic)
Srel ⇒ same: Sfast−Sslow ; opposite: S₁+S₂ ; meet: D/Srel
Train: pole→LT ; platform→LT+LP ; two trains→LT₁+LT₂ with Srel
Boats: D=B+C, U=B−C ; B=(D+U)/2, C=(D−U)/2 ; escalator same
Race ⇒ head x→A D, B D−x ; circular meet→circum/Srel
Late/early ⇒ D/Sold − D/Snew = ΔT
Primary source: none pinned yet — drop your preferred video/book resource into RESOURCES.md and it will be linked here. Ask me anything that's unclear.
Questions? Ask your agent — you can follow up on any concept, quiz answer, or get extra practice problems tuned to this module.