A tank is a work-rate problem with signs — inlets do
positive work (+), outlets/leaks do negative work (−). The
LCM method turns fractions 1/x into clean integer rates so you never solve with
fractions under time pressure.
Fundamental rule: If A fills in x hours and B empties in
y hours:
Rate A = +1/x, Rate B = −1/y, Net =
1/x − 1/y
Instead of fractions like 1/20, assume a concrete capacity:
Rate = Capacity / Time — assign negative to outlets.
Capacity / Net rate1/10−1/15=1/30 → 30 min — same answer, but LCM keeps
everything integer.
If A fills in x and B in x+10, together in T:
1/x + 1/(x+10) = 1/T → solve quadratic for x. Use LCM method when
times are fixed numbers; use equation when one time is expressed in terms of another.
Leak = outlet. Normally fills in 10h but takes 12h due to leak →
1/10 − Rate(Leak) = 1/12 → Rate(Leak)=1/10−1/12=1/60 → leak empties
full tank in 60h.
Pattern: "takes longer" → subtract leak rate; "empties in y hours alone" → that's the leak's time.
Pipes open one after another (e.g., A 1 min, then B 1 min):
Rate(A)+Rate(B) per 2 min — but do NOT blindly divide total
capacity by cycle work if a cycle contains a negative step.
A opens at 8:00, B at 9:00:
If rate changes (e.g., "drops by 50%" after some time):
If outlet pumps 10 L/min and LCM method says it empties full tank in T minutes → total
capacity = T × 10 L. Convert rate×time to actual volume.
| Symbol | Meaning |
|---|---|
C |
Capacity (LCM of times, in units) |
R |
Flow rate (units/min) |
+ve / −ve |
Filling / emptying sign |
T |
Total time |
A fills +1/10, B empties −1/15 → net?
LCM method: A 10m, B 15m → capacity?
In that LCM, rates are?
Normally fills in 10h, with leak takes 12h → leak empties in?
Alternating A(+5) then B(−2), capacity 30 — blind cycle division fails because?
A (8am) + B (9am) → first hour work by?
Outlet pumps 10 L/min, empties full tank in 30 min → capacity?
Inlet ⇒ + ; Outlet/leak ⇒ − ; net = 1/x −1/y ; +→fills, −→empties
Capacity ⇒ LCM(times) ; Rate ⇒ Capacity/Time (sign matters) ; Time ⇒ Capacity/net
(eg A10,B15→30 units→+3,−2→net+1→30 min)
a) Leak ⇒ 1/10−x=1/12 → x=1/60 → empties 60h
b) Alternating ⇒ cycle=+ sum but reserve last +fill; don’t blind divide
c) Staggered ⇒ solo work → remaining/COMBINED
d) Variable rate ⇒ phase-wise work then sum times
Capacity ⇒ T(empty)×rate (eg 30×10=300L)
Primary source: none pinned yet — drop your preferred video/book resource into RESOURCES.md and it will be linked here. Ask me anything that's unclear.
Questions? Ask your agent — you can follow up on any concept, quiz answer, or get extra practice problems tuned to this module.