2D mensuration measures flat shapes — boundary (perimeter) and space occupied (area). Every formula is either counting squares (area) or walking the edge (perimeter). Learn the general case, then the shortcuts for regular shapes.
aa²4aa√2 — by Pythagoras on half-square.l, width bl × b2(l + b)√(l² + b²) — Pythagoras on half-rectangle.(1/2) × base × height (height is perpendicular
to that base).
a, b, c known):s = (a+b+c)/2
(semi-perimeter), Area = √[s(s−a)(s−b)(s−c)]a): Area = (√3/4) a², Height =
(√3/2) a. Derive from Pythagoras on half-equilateral (30-60-90 triangle).
r, diameter d = 2rπr²2πr = πdπ ≈ 22/7 when r is a multiple of 7; otherwise 3.14.a√2 (1.414×), rectangle needs Pythagoras. If a problem gives you a diagonal,
square it immediately: a = diagonal/√2.
Area: base × height (height is perpendicular distance between bases, not side
length). Perimeter: 2 × (sum of adjacent sides).
a, b, height
h
Area: (1/2) × (a + b) × h — average of parallel sides times distance between
them. Think of it as "trapezium is half a parallelogram".
n × s(3√3/2) s² — 6 equilateral triangles, same as in Geometry (Module
23).
(1/2) × perimeter × apothem (apothem = distance from center to
midpoint of a side). Useful when apothem is given.
Part enclosed by two radii and an arc, central angle θ:
(θ/360) × πr²(θ/360) × 2πr2r sin(θ/2)(1/2) r² sin θ, so segment = (θ/360)πr² − (1/2)r² sin θ.
60/360 × 22/7 × 196 = 1/6 × 616 = 102.67. Arc =
60/360 × 2×22/7×14 = 14.67. Choose π=22/7 because r is multiple of 7 — avoids
decimals.
Diagonal of rectangle = diameter of circle:
l² + b² = (2r)². Every corner of the rectangle touches the circle — so the
diagonal is a diameter (Thales' theorem: angle in a semicircle is 90°).
| Situation | Relation |
|---|---|
| Inscribed circle (inside square) | Diameter = side of square → 2r = a |
| Circumscribed circle (square inside circle) | Diameter = diagonal of square → 2r = a√2 |
r (incircle): r = Area / s where s =
semi-perimeter. Derivation: area = sum of three triangles with height r.
R (circumcircle):
R = (a×b×c) / (4×Area)
(P + B − H)/2, Circumradius =
H/2 (hypotenuse is diameter).
Rectangle l × b, path width w outside:
l + 2w, Outer width: b + 2w (w on both sides)(l+2w)(b+2w) − lb
= 2w(l + b + 2w)l − 2w, Inner width:
b − 2w
lb − (l−2w)(b−2w) = 2w(l + b − 2w)Pitfall: Outside adds 2w, inside subtracts 2w — but students forget the factor 2 (w on both sides). A 2m border around a rectangle adds 4m to total length.
| Symbol | Meaning |
|---|---|
l, b, h |
Length, breadth, height |
a, s |
Side length |
r, R |
Inner / outer radius |
d |
Diameter or diagonal |
P |
Perimeter |
A |
Area |
θ |
Central angle (degrees) |
π |
≈ 22/7 or 3.14 |
Diagonal of a square side a is?
Area of equilateral triangle side a?
Heron's formula uses?
Area of sector with angle θ?
Chord length for central angle θ in circle radius r?
Rectangle in a circle: diagonal = ?
Incircle radius of a triangle (area A, semi-perimeter s)?
Right triangle (3-4-5): inradius?
Path width w outside rectangle l×b: outer length?
Perimeter ⇒ walk the edge ; Area ⇒ count squares
Square ⇒ a², 4a, diag a√2 ; Rectangle ⇒ l×b, 2(l+b), diag √(l²+b²)
Triangle ⇒ (1/2)bh ; Heron √[s(s−a)(s−b)(s−c)] ; Equilateral (√3/4)a², height (√3/2)a
Circle ⇒ πr², 2πr ; π≈22/7 (r multiple of 7)
Parallelogram ⇒ base×height (perp) ; Trapezium ⇒ (1/2)(a+b)×h
Regular n-gon ⇒ n×s ; hexagon (3√3/2)s² ; general (1/2)×perimeter×apothem
Sector ⇒ (θ/360)πr² ; arc (θ/360)2πr ; Chord 2r sin(θ/2)
Segment = sector − triangle (1/2)r² sin θ
Rect in circle ⇒ diagonal = diameter ; l²+b²=(2r)²
Circle in square ⇒ 2r=a ; Square in circle ⇒ 2r=a√2
Triangle: inradius r=A/s ; circum R=abc/4A
Right: r=(P+B−H)/2 ; R=H/2
Outside w ⇒ (l+2w)(b+2w) ; area = outer−inner =2w(l+b+2w)
Inside w ⇒ (l−2w)(b−2w) ; area =2w(l+b−2w)
l,b,h ⇒ length/breadth/height ; r,R ⇒ radius ; θ ⇒ angle ; P/A ⇒ perimeter/area
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