Age problems are linear equations in disguise — past, present, future with one constant: time moves equally for everyone. Placexat present, shift by±n, and the ratio does the rest.
| Rule | Statement | Example |
|---|---|---|
| 1. Time travel is universal | If n years pass, everyone ages n years |
Father x, Son y → after 5y: x+5, y+5
|
| 2. Difference is constant | Age gap never changes | Brother 5y older today → still 5y older in 50 years |
| 3. Ratio changes | Multiples/ratios are snapshot-specific | Father 3× Son today → not 3× after 10y |
Why Rule 3 matters: ratio 3:1 today means gap = 2 units. Adding 10y to both keeps gap same but total grows, so ratio shrinks. Never carry a ratio across time without shifting both ages.
Place x at present — then past/future are offsets:
| Timeline | Keywords | Expression |
|---|---|---|
| Past | ago, before, back then, was | x − n |
| Present | now, current, at present, is | x |
| Future | hence, after, from now, will be | x + n |
ax, bx immediately — not
x, y. One variable is enough. For "20 years older", one variable is also enough
(x, x+20), not two.
4x, 5x → after 5y: 4x+5, 5x+5(4x+5)/(5x+5)=5/6 → cross: 6(4x+5)=5(5x+5) →
24x+30=25x+25 → x=5Since age difference is constant, the gap in ratio units must be same at both times — compare the change in units directly.
1 unit =5y → now: 4×5=20, 5×5=25 instantly.Total age = Average × NA+Y (if
no one leaves/joins) — everyone ages equally.
(32×2+0)/3≈21.3 immediately.
High-level template: "A is twice as old as B was when A was as old as B is now."
A, B, gap D = A−B.D years ago (because A has aged D since then
to reach current A).A−D = B, B's age was B−D.A = 2×(B−D) = 2×(B − (A−B)) = 2×(2B−A) → 3A = 4B.D is the time shift between "now" and "then".
| Symbol | Meaning |
|---|---|
x, y |
Present ages (usually one variable suffices) |
n, t |
Years ago/hence |
a:b |
Ratio → ax, bx |
Average |
Sum / count |
Time travel rule: after n years, ages become?
Age difference over time?
Ratio now 4:5 → present ages?
Ratio 4:5 now, 5:6 after 5y — using equation, x=?
Constant-difference shortcut for 4:5 → 5:6 in 5y: 1 unit = ?
Average of N people is A today. After Y years (same group) average = ?
"A is twice as old as B was when A was as old as B is now" — first step?
Universal ⇒ +n to everyone ; Gap ⇒ constant ; Ratio ⇒ changes (snapshot only)
Present = x ; Past ⇒ x−n ; Future ⇒ x+n
Ratio a:b ⇒ ax,bx ; Times ⇒ Son=x, Father=3x ; Older ⇒ B=x, A=x+20
a) Equation ⇒ define now → shift → new ratio → solve (eg 4:5→5:6 in 5y →x=5)
b) Constant diff ⇒ gap in units same → 1 unit = years changed (scale to equalize diff if needed)
Total = Avg×N ; group +Y years → avg +Y ; baby (0) → avg drops sharply
"When A was as old as B now" ⇒ D years ago → A−D=B, B−D ; then statement → A=2(B−D)
Primary source: none pinned yet — drop your preferred video/book resource into RESOURCES.md and it will be linked here. Ask me anything that's unclear.
Questions? Ask your agent — you can follow up on any concept, quiz answer, or get extra practice problems tuned to this module.