A clock is a circular race — minute hand at 6°/min, hour hand at 0.5°/min,
relative speed 5.5°/min. Every angle problem is |30H − 5.5M| with a reflex check;
every faulty-clock problem is a ratio of real vs indicated time.
360/12 = 30° per hour number360/60 = 6° per minute mark| Hand | Speed | Derivation |
|---|---|---|
| Minute hand | 6°/min |
360° /60 min |
| Hour hand | 0.5°/min |
360° /720 min (12h) |
| Relative (minute gains) | 5.5°/min =11/2 |
6 −0.5 (same direction) |
Relative speed is the lap speed — minute hand laps the hour hand every
720/11 ≈65.45 min (not 60 — because hour hand moves).
Standard formula: at H hours and M minutes:
θ = |30H − 5.5M| = |30H − (11/2)M|
H is hour digit (12 → 0), M is minutes. θ is internal
(smaller) angle. If θ >180°, smaller angle = 360 − θ (reflex is
the larger).
θ=|30×3 −5.5×15|=|90−82.5|=7.5°. At 3:00 →
|90−0|=90°. At 6:00 → |180−0|=180° (straight line). At 12:00 →
|0−0|=0° (overlap).
Given angle (0° overlap, 180° straight, 90° right), find M between H and H+1:
30Hθ_des (e.g., 0, 90, 180)|θ_des − 30H| (handling wrap) or more generally
5.5M = |30H − θ_des|
M = Distance / 5.5
Example: Between 3 and 4, when are hands at 90°? At 3:00 angle 90° already (so M=0 is one
solution). Second solution: need angle 90° on the other side → distance = 180−90=90° beyond?
Actually between 3–4, after 3:00 the minute gains: solve |90−5.5M|=90 → M=0 or
M=180/5.5≈32.73 min → times 3:00 and ~3:32:43.
| Position | Angle | Times in 12h | Times in 24h |
|---|---|---|---|
| Coincide (overlap) | 0° | 11 | 22 |
| Straight line (opposite) | 180° | 11 | 22 |
| Right angle | 90° | 22 | 44 |
Missing instance: No overlap between 11:00 and 1:00 — they coincide at exactly 12:00, counted once, so 11 not 12.
Correct time : faulty time → find real duration for a given indicated duration.
If a clock gains x minutes per 24h of real time:
Faulty covers 24h + x in 24h real →
True Time = Indicated Duration × 24 / (24 + Gain)
Loses x → denominator 24 − x (since faulty covers less).
48×24/(24+5/60)? Actually x in hours: 5 min =0.0833h → true
=48×24/(24.0833)=47.83h ≈47h 50m. For quick MCQs, use minutes: true = indicated
×1440/(1440+gain_minutes).
If hour hand speed is not 0.5°/min (e.g., 0.7°/min as in puzzle): redefine relative speed =
|MinuteSpeed − HourSpeed|, then reuse overlap/angle logic: time to next overlap =
360 / RelativeSpeed.
| Symbol | Meaning |
|---|---|
H |
Hour (1–12, 12→0) |
M |
Minutes (0–60) |
θ |
Angle in degrees |
5.5 =11/2 |
Relative speed °/min |
T |
Total real time elapsed |
Error |
Indicated − True |
Hour space in degrees?
Minute hand speed?
Relative speed minute vs hour?
Angle at 3:15?
If θ>180°, smaller angle is?
How many overlaps in 12h?
Clock gains 6 min per 24h → true time for 24h indicated?
360° total ; hour 30° ; minute 6°
Minute 6°/min ; Hour 0.5°/min ; Relative 5.5=11/2 ; lap ≈65.45 min
θ=|30H−5.5M| ; if >180 → 360−θ ; 3:15→7.5°, 3:00→90°, 6:00→180°
Time for angle: M=|30H−θ|/5.5
Overlap/straight:11 in 12h (22 in 24h) ; right:22 in 12h (44 in 24h) ; none 11→1
True = Indicated×24/(24±gain) ; gains + , loses −
Custom: new relative = |M_speed − H_speed|
Primary source: none pinned yet — drop your preferred video/book resource into RESOURCES.md and it will be linked here. Ask me anything that's unclear.
Questions? Ask your agent — you can follow up on any concept, quiz answer, or get extra practice problems tuned to this module.